Question

Draw the graph of the given Polynomial and findthe zeroes
$x2 - x - 12$
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Answer 1

Answer:

${x}^{2} - x - 12$

$= {x}^{2} - (4 - 3)x - 12$

$= {x }^{2} - 4x + 3x - 12$

$= x(x - 4) + 3(x - 4)$

$= (x - 4)(x + 3)$

$⟹x - 4 = 0 \: and \: ⟹x + 3 = 0$

$⟹x = 4 \: and \: x = - 3$

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Answer 2

Step-by-step explanation:

hope it will help you ans in image