Question

Draw the Graph of the given polynomial p(x) and find the zeroes p(x)=x^2+7x+10

Answer 1

Answer:

(i)x

2

+7x+10

x

2

+(2+5)x+10

x

2

+2x+5x+10

x(x+2)5(x+2)

(x+2)(x+5)ans

(ii)(x)

2

+2×x×

2

7

+(

2

7

)

2

−(

2

7

)

2

+10

(x+

2

7

)−

4

49

+10

(x+

2

7

)−

4

49+40

(x+

2

7(

)−

4

9

(x+

2

7

)−(

2

3

)

2

a

2

−b

2

=(a+b)(a−b)

(x+

2

7

+

2

3

)(x+

2

7

−

2

3

)

(x+

2

10

)(x+

2

4

)

(x+5)(x+2)

Is the answer

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Answer 2

x

2

−7x+10

=x

2

−2x−5x+10

=x(x−2)−5(x−2)

=(x−2)(x−5)

As, (x−2) and (x−5) are the factors of the given polynomial,so,

Zeroes of the polynomial are: 2 and 5.

Therefore, option C is correct.

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