Question

Draw the graph of the linear equation 2 x + 3 y = 12. At

what points, the graph of the equation cuts the X & Y axes?​

Answer 1

Answer:

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Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

TO DETERMINE

• To draw the graph of the linear equation 2 x + 3 y = 12

• The points where the graph of the equation cuts the X & Y axes

EVALUATION

The given equation of the line is

$\displaystyle \sf{2x + 3y = 12}$

Which can be rewritten as

$\displaystyle \sf{ \frac{2x}{12} + \frac{3y}{12} = 1 }$

$\implies \: \displaystyle \sf{ \frac{x}{6} + \frac{y}{4} = 1 }$

Which is of Intercept form

So the line cuts X axis at A ( 6, 0) and Y axis at B ( 0, 4)

GRAPH : The graph of the given linear equation is referred to the attachment

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LEARN MORE FROM BRAINLY

Find the area of triangle bounded by

a line 4x+3y=48 with coordinate axes. 

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