Question

Draw the graph of the linear equation: 3x+4y=12. At what points,the graph cuts the x-axis and y-axis.

Answer 1

To find where the line of the equation cuts X axis, put y=0.
3x + 4y=12
3x + 4* 0 =12
x =12/3=4
It cut x-axis at (4,0)
To find where the line of the equation cuts Y axis, put x=0.
3x + 4y=12
3*0  + 4 y=12
y   =12/4 = 3.
It cut y-axis at 3,0

Answer 2

Answer:

It cut x-axis at (4,0) and y-axis at (3,0)

Step-by-step explanation:

To find where the line of the equation cuts X axis, put y=0.

3x + 4y=12

3x + 4* 0 =12

x =12/3=4

It cut x-axis at (4,0)

To find where the line of the equation cuts Y axis, put x=0.

3x + 4y=12

3*0  + 4 y=12

y   =12/4 = 3.

It cut y-axis at 3,0