Math, asked by raghurajraj560, 5 months ago

Draw the graph of the linear equation 3x -y =4, from the graph , find the values of h & k if the graph passes through the points (h,-4) & (3,k).​

Answers

Answered by patelmeshwa751
0

Answer:

★QuestioN★:−

Discuss the nature of the roots of the following equations.

\bf{4x^2-12x+9=0}4x

2

−12x+9=0

\pink\bf{\bigstar{AnsweR}\bigstar:-}★AnsweR★:−

✧To find the nature of roots, we have to use the formula for discriminant.

\bf{Discriminant = b^2 - 4ac}Discriminant=b

2

−4ac

✧Here,

:\longrightarrow\green\bf{a=4~,b=-12~, c=9}:⟶a=4 ,b=−12 ,c=9

✧On applying formula,

:\implies\red\bf{b^2-4ac=(-12)^2-4\times4\times9}:⟹b

2

−4ac=(−12)

2

−4×4×9

:\implies\red\bf{144-4\times4\times9}:⟹144−4×4×9

:\implies\red\bf{144-144}:⟹144−144

{\boxed{\underline{\bf{\sf{\red{\bigstar0\bigstar}}}}}

✧Here,

✧D = 0

✧That's why the equation have two equal real roots!!

\huge{\boxed{\underline{\bf{\sf{\red{\bigstar{Extra~Info:-}\bigstar}}}}}

⟿ Nature of roots are based on the discriminant.

⟿ According to that, three types are there. They are,

  • q

Two distant real roots.

Two equal real roots.

No real roots.

⟿ Nature of roots of quadratic equations by using quadratic formula,

Two distant real roots if, b² - 4ac > 0.

Two equal real roots if, b² - 4ac = 0

No real roots if, b² - 4ac < 0.

  1. Happy Learning Dear!!♡

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