Question

Draw the graph of the linear equations 2x-3y+6=0 and 4x+3y=24 on
the same graph paper. Use the graph drawn to find the point of
intersection of these two lines and the area of triangle enclosed by
the lines and x axis.​

Answer 1

Answer:

solution

The given simultaneous equations are 4x+3y=34 and 4x-3y=-24

4x+3y=24.......(i)

y=(24-4x)/3

4x-3y=-24.......(ii)

y=(4x+24)3

from the graph A(-6,0),B(0,8) (6,0)andAC=12unit

Height=h=8unit

Base=b=12unit

Area of triangle=(1/2)*base*height

A(ΔABC) =(1/2)*12*8

A(ΔABC) =48sq unit

Step-by-step explanation:

I hope it is help you