Question

Draw the graph of the pair of equations x-2y=4 and 3x+5y=1. From the graph, find the values of X and Y which will satisfy both equations. Write the vertices of the triangle formed by these lines and the Y axis. Find the area of this triangle.

Answer 1

Answer:

$-2.2$.

Step-by-step explanation:

We have been given pair of equation

$x-2y=4$   (i) and $3x+5y=1$   (ii).

To find the graph,we find the value of x and y from the given equation:

if x=0

$x-2y=4\\0-2y=4\\y=-2$

(0,-2)

if x=0,substitute the value in second equation

$3x-5y=1\\3(0)-5y=1\\y=0.2$

(0,0.2)

Find the value of x and y from equation (i) and (ii) before making the equation same so that we cancel out the same.

Subtract the value of equation (ii) from equation (i)..

$3x-6y=12\\3x+5y=1\\-11y=11\\y=-1$

Substitute the value of y in equation (i)

$x-2y=4\\x-2(-1)=4\\x+2=4\\x=2$

(x,y)=(2,-1)

Area of triangle ABC=

$=\frac{1}{2}[x1(y2-y3)+x2(y3-y1)+x3(y1-y2) ]\\=\frac{1}{2} [2(-2-0.2)+0(0.2+1)+0(-1+2)\\=\frac{1}{2}[2(-2.2)]\\=\frac{1}{2}[-4.4]\\ =-2.2$

Thus,the area of triangle is $-2.2$.

Answer 2

Step-by-step explanation:

that photo contains the right answer and proper explanation

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