draw the graph of the polynomial and find the zeroes also justify your answer.if f(x)=x2-2x-15
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f(x)=x2−2x−8
to find the vertex, we know,
x=−2ab=−2×1−2=1
to find y coordinate, substitute the value of x in equation.
(1)2−2(1)−8=1−2−8=9
The vertex is (1,9)
Now, x intercepts,
x2−2x−8=0
(x−4)(x+2)=0
x=−2,4
The x intercepts are (−2,0),(4,0)
To find the y intercept, substitute x=0 in given equation,
02−2(0)−8=−8
The y intercept is (0,−8)
Thus it is an upward facing parabola, touching x and y axis at (2,−8),(−1,−5),(3,−5)
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