Question

draw the graph of the polynomial p(x)=x^2-x-12 and find the zeros​

Answer 1

Answer:

Answer:

The number of zeros of the polynomial function is determined by the number of points it intersects the x-axis

(i) p(x) = x² – x – 12

Here, the number of zeros are 2 and the zeros are the points where the graph of the polynomial intersects the x-axis.

Zeros are : (-3 , 0) and (4 , 0)

(ii) p(x) = x² – 6x + 9

Here, the graph of the polynomial intersects the x-axis at one point.

Zeros are : (3 , 0)

(iii) p(x) = x² – 4x + 5

Here, the graph of the polynomial do not intersects the x-axis at any point so the given polynomial has no real zeros

(iv) p(x) = x² + 3x – 4

Here, the graph of the polynomial intersects the x-axis at 2 points.

Zeros are : (-4 , 0) and (1 , 0)

(v) p(x) = x² – 1

Mark me as a brainliest

Answer 2

Answer:

Graph of x² - x - 12 = 0 is in Attachment ✅

x² - x - 12 = 0

x² - 4x + 3x - 12 =0

x(x - 4) + 3(x - 4) = 0

(x - 4) or (x + 3) = 0

x = 4 or x = -3 ..........Zeros of polynomial