Question

Draw the graph of the polynomial p(x)=x2-4x+5 and find its zeroes.

Answer 1

Step-by-step explanation:

for any value of x , the value of y is always positive.thus there is no real value of x for which y becomes zero.

and hence ,there is no real zeros of the given polynomial.

please refer to the attachment

I hope it would help you

thank you

Answer 2

Given:

Polynomial $p(x)=x^{2} -4x+5$

To find:

The zeroes of the polynomial and its graph.

Solution:

To find its zeroes of the polynomial equation, lets use the Shri Dharacharya formula:

x=(-b±√(b²-4ac))/(2a)

Here, a = 1, b = -4, c = 5.

On substituting the values of a, b, c, we get:

x = (-(-4)±√((-4)²-4×(1)×(5)))/(2×1)

x = (4 ± √(-4))/ (2)

x = 2 ± i

Thus, the zeroes of the given polynomial will be 2 ± i, and the graph of the polynomial is attached with this answer.