Math, asked by jahnavi3584, 2 months ago

Draw the graph of the polynomial x^-4x-5 find the zeroes and justify your answer.​

Answers

Answered by amansharma264
10

EXPLANATION.

Graph of the equation.

⇒ x² - 4x - 5 = 0.

As we know that,

⇒ y = x² - 4x - 5 = 0.

Factorizes the equation into middle term splits, we get.

⇒ y = x² - 5x + x - 5 = 0.

⇒ y = x(x - 5) + 1(x - 5) = 0.

⇒ y = (x + 1)(x - 5) = 0.

Zeroes of the equation, we get.

⇒ x = - 1  and  x = 5.

Put the value of x = -1 in equation, we get.

⇒ y = (-1)² - 4(-1) - 5.

⇒ y = 1 + 4 - 5.

⇒ y = 5 - 5.

⇒ y = 0.

Their Co-ordinates = (-1,0).

Put the value of x = 5 in equation, we get.

⇒ y = (5)² - 4(5) - 5.

⇒ y = 25 - 20 - 5.

⇒ y = 25 - 25.

⇒ y = 0.

Their Co-ordinates = (5,0).

Put the values of x = 0 in equation, we get.

⇒ y = (0)² - 4(0) - 5.

⇒ y = -5.

Their Co-ordinates = (0,-5).

Attachments:
Answered by xXMarziyaXx
0

EXPLANATION.

Graph of the equation.

⇒ x² - 4x - 5 = 0.

As we know that,

⇒ y = x² - 4x - 5 = 0.

Factorizes the equation into middle term splits, we get.

⇒ y = x² - 5x + x - 5 = 0.

⇒ y = x(x - 5) + 1(x - 5) = 0.

⇒ y = (x + 1)(x - 5) = 0.

Zeroes of the equation, we get.

⇒ x = - 1  and  x = 5.

Put the value of x = -1 in equation, we get.

⇒ y = (-1)² - 4(-1) - 5.

⇒ y = 1 + 4 - 5.

⇒ y = 5 - 5.

⇒ y = 0.

Their Co-ordinates = (-1,0).

Put the value of x = 5 in equation, we get.

⇒ y = (5)² - 4(5) - 5.

⇒ y = 25 - 20 - 5.

⇒ y = 25 - 25.

⇒ y = 0.

Their Co-ordinates = (5,0).

Put the values of x = 0 in equation, we get.

⇒ y = (0)² - 4(0) - 5.

⇒ y = -5.

Their Co-ordinates = (0,-5).

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