Question

Draw the graph of the polynomial x^-x-12 find the zeroes and justify your answer​

Answer 1

Answer:

${x}^{2} - x - 12 = 0 \\ {x}^{2} - 4x + 3x - 12 = 0 \\ x(x - 4) + 3(x - 4) = 0 \\ (x - 4)(x + 3) = 0 \\ x - 4 = 0 \: \: \: or \: \: \: x + 3 = 0 \\ x = 4 \: \: \: or \: \: \: x = - 3$