Draw the graph of two lines whose equations are 3x-2y+6=0 and x+2y-6=0 on the same graph paper.Find the area of the triangle formed by the two lines and the x-axis.
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SOLUTION:-
Refer all Attachment.
The triangle so formed by equation of line and x axis you can see.
coordinates of points
A = (x1,y1) = (0,3)
B = (x2 ,y2) = (6,0)
C = (x3, y3) = (-2, 0)
D = (x, y) = (0,0) coordinate of origin.
•°• The distance of AD from origin is 3unit.
•°• AD = 3 .....(1)
now,
By distance Formula
d(B,C) = √((x3 - x2)² + (y3 - y2)²)
= √((-2 - 6))² + (0 - 0)²)
= √((-8)² + 0)
= √(64)
= 8
d(B, C) = 8 unit
•°• BC = 8 ....(2)
Now,
Area of triangle so formed = 1/2 × AD × BC
= 1/2 × 3 × 8
= 4 × 3
= 12sq unit
The area of the triangle formed by the two lines and the x-axis 12 sq unit
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