Question

Draw the graph of velocity versus time where ball is thrown upward with 10
m/s. (g= 10 m/s2)

Answer 1

Given :-

• Initial velocity (u) = 10 m/s

• Acceleration due to gravity (g) = 10 m/s²

Plotting V vs t graph :-

• Time of ascent = u/g = 1 sec

• At highest point, v = 0 (at 1 sec)

• Time of descent = u/g = 1 sec

So, Graph is as shown in attachment.

Answer 2

Given:

Initial velocity, u = 10 m/s.

Acceleration, a = g = 10 m/s².

To Find:

Using the given data, we have to draw the graph of velocity versus time, where ball is thrown upward with initial velocity 10m/s.

Solution:

At u = 10 m/s, time, t = 0 s.

The velocity is calculated using the equation;

V = u + a × t.

As the ball is thrown upward against the gravitational force, here the acceleration due to gravity is negative.

V = u - g × t.

This is the equation for a straight line with slope:

y = (-g) x + c.

Now we have to find the starting point and end point of the graph.

At the point where the ball reaches maximum height, the velocity (v) is zero.

Time at that point is calculated using the above equation.

$V = u - g × t.\\\\0 = 10 - (-10) × t\\\\i.e., t = 1 s.$

When ball reaches back to ground, the velocity becomes -10 m/s.

Value of t for v = -10 m/s is,

$t = \frac{(v - u)}{-g}$

$t = \frac{(-10) - 10}{-10} = \frac{-20}{-10} = 2.$

Therefore, the graph is a straight line with starting point (0, 10) and end point  (2, -10).

The graph of velocity versus time, where ball is thrown upward with velocity 10 m/s is given below.

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