Question

draw the graph of x - y = 2, from the graph check whether x=2, y=2 is a solution of the given equation or not.​

Answer 1

Answer:

(i)Solution:

Given equations are 3x + y + 4 = 0

6x – 2y + 4 = 0

Here a1 = 3, b1 = 1, c1 = 4

a2 = 6, b2 = –2, c2 = 4

\frac{a_{1}}{a_{2}}= \frac{3}{6}= \frac{1}{2},\frac{b_{1}}{b_{2}}= \frac{-1}{2},\frac{c_{1}}{c_{2}}= \frac{4}{4}= \frac{1}{1}

\frac{a_{1}}{a_{2}}\neq \frac{b_{1}}{b_{2}}

Hence the given pair of linear equations are intersecting at one point.

Hence given pair of linear equations is consistent

Let as plot the graph of given equations

In equation 3x + y + 4 = 0

x 0 -1 -2

y -4 -1 2

In equation 6x – 2y + 4 = 0

x 0 -1 -2

y 2 -1 -4