Draw the graph of x+y=6 which intersects the x -axis and y-axis at A and B respectively. Find the length of seg AB . Also find the area of ∆AOB where point O is origin.
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Answered by
54
by substituting y=0, we get x=6 on x-axis
by substituting x=0, we get y=6 on y-axis
so A=(6,0), B=(0,6) by using two point distance form AB length=8.485units as it's a right angle isosceles triangle with OA as height and OB as base, the area of the triangle OAB is 18sq.units
by substituting x=0, we get y=6 on y-axis
so A=(6,0), B=(0,6) by using two point distance form AB length=8.485units as it's a right angle isosceles triangle with OA as height and OB as base, the area of the triangle OAB is 18sq.units
gaurav999979:
Thank you sir . my hots problem solving on it.
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Answered by
20
then area of triangle AOB = 1/2× base ×height
=1/2×6×6
=1/2×36
=18 square unit
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