Question

Draw the graph of x²– 2x + 8 and find zeroes.

Answer 1

Answer:

Here goes the solution!

Given,

f(x) = x²– 2x + 8

to find the vertex, we know,

x = -b/2a = -2/2×1 = 1

to find y coordinate, substitute the value of x in equation.

( 1 )² - 2( 1 ) - 8 = 1 - 2 - 8 = 9

The vertex is ( 1 , 9 )

Now, x intercepts,

x²– 2x - 8 = 0

( x - 4 ) ( x + 2 ) = 0

x = -2, 4

The x intercepts are ( −2, 0 ),( 4 , 0 )

To find the y intercept, substitute x=0 in given equation,

0² - 2( 0 ) - 8 = -8

The y intercept is (0,−8)

Thus it is an upward facing parabola, touching x and y axis at (2,−8),(−1,−5),(3,−5).

Step-by-step explanation:

See the attachment!