Question

draw the graph of x²-x-12 and find its zeros​

Answer 1

Answer:

photo answers and graph

Step-by-step explanation:

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Answer 2

Refer to the attached image for the graph. The zeroes are 4 and (- 3).

Step-by-step explanation:

Drawing the graph.

The given polynomial is

y = x² - x - 12

➜ y = (x - ½)² - ¼ - 12

➜ y = (x - ½)² - 49/4

➜ y + 49/4 = (x - ½)²

This is a parabola whose vertex is at (½, - 49/4). This is a concave up parabola.

Refer to the attached image.

• [ Note: you can draw the parabola by putting some x and find their respective y values, and then plot them to find the graph. ]

Also, y = x² - x - 12

➜ y = x² - 4x + 3x - 12

➜ y = x (x - 4) + 3 (x - 4)

➜ y = (x - 4) (x + 3)

This shows that the parabola intersects the x-axis at (4, 0) and (- 3, 0).

Finding the zeroes.

Given polynomial is

x² - x - 12

= x² - 4x + 3x - 12

= x (x - 4) + 3 (x -4)

= (x - 4) (x + 3)

So either x - 4 = 0 or, x + 3 = 0

➜ x = 4, x = - 3

Thus the zeroes are 4 and (- 3).

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