Draw the graph of y=6-x-x2
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vertex is (-1/2, 25/4) and roots are 2 and -3 .
we have to draw y = 6 - x - x². perhaps you know it is a quadratic equation. graph of any quadratic equation is parabolic.
as coefficient of x² is negative. so parabola will open vertically downward as shown in figure.
let see discriminant to observe location of vertex.
D = (-1)² - 4(-1)(6) = 25
vertex is given by, (-b/2a, -D/4a)
so, {-(-1)/2(-1), -(25)/4(-1)} = {-1/2, 25/4}
now let's find point of intersection with x - axis. (i.e., roots of quadratic)
6 - x - x² = 0
⇒6 - 3x + 2x - x² = 0
⇒3(2 - x) + x(2 - x) = 0
⇒(2 - x)(3 + x ) = 0
⇒x = 2 , -3
now we are plotting the graph. you can see final graph of y = 6 - x - x².
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