Question

Draw the graph of y=x^2+3x-4 and find the zeros​

Answer 1

Solution: If x = 0, ⇒ y= 02 - 3(0) - 4 = - 4 If x = 1 ⇒ y= 12 - 3(1) - 4 = - 4 = 1 - 3 - 4 = - 6 If x = -1 ⇒ y = y= (-1)2 - 3(-1) - 4 = 1+3 - 4 = 0 If x = 4 ⇒ y = (-1)2 - 3(4) - 4 = 16 - 12 - 4 = 0 The coordinate points of the given equation are

x

0

1

- 1

4

y

- 4

- 6

0

0