Math, asked by ashwin100, 11 months ago

Draw the graph of y=x^2-4 and hence solve x^2-x-12=0​

Answers

Answered by acesolution2017
9

Answer:

Step-by-step explanation:

I have attached the graph for y = x2 - 4;

Solution of x^2-x- 12 = 0;

we can write this eq. like;

x^2 - 4x + 3x -12 = 0;

x (x-4) + 3 (x-4) = 0;

(x-4) (x+3) = 0

X = 4 and -3

there are two liine both are parallel to each other and passing through x= 4 and -3

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