Draw the graph of y=x^2-4 and hence solve x^2-x-12=0
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Step-by-step explanation:
I have attached the graph for y = x2 - 4;
Solution of x^2-x- 12 = 0;
we can write this eq. like;
x^2 - 4x + 3x -12 = 0;
x (x-4) + 3 (x-4) = 0;
(x-4) (x+3) = 0
X = 4 and -3
there are two liine both are parallel to each other and passing through x= 4 and -3
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