Question

draw the graph ofp(x)=x2-,x-12 and find zeroes justify your answer​

Answer 1

Answer

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p(x)=x²-x-12

p(x) = x² - 4x + 3x - 12

=> p(x) = x(x - 4) + 3(x - 4)

=>  p(x) = (x + 3)(x - 4)

x           p(x) =x²-x-12

5            8

4            0

3            -6

2            -10

1             -12

0.5         -12.25

0            -12

-1            -10

-2           -6

-3            0

-4            8

roots/Zeros

x = - 3

x = 4

Minimum value  - 12.25  at  x = 0.5

Graph symmetric about x = 0.5

Step-by-step explanation: