draw the graphs for these two polynomials and write steps of construction...no spamming..
Answers
Step-by-step explanation:
Step-by-step explanation:
Given : Polynomial p(x)=x^2-x-12p(x)=x2−x−12 .
Solution :
We plot the graph of polynomial on different value of x and y,
Since it is quadratic function it form a parabola.
The number of zeros are 2 and the zeros are the points where the graph of the polynomial intersects the x-axis.
Zeros are : (-3,0) and (4,0)
On y-axis the point is (0,-12).
The vertices of the parabola is (0.5,-12.25)
2.Consider the provided polynomial.
f(x)=x^2-6x+9f(x)=x2−6x+9
The provided equation is a quadratic equation.
Now compare the provided equation with standard equation ax^2+bx+cax2+bx+c .
a=1, b=-6 and c=9
Since, the value of a is a positive number that means the graph of the equation is an upward parabola.
Substitute x=0 in above equation
f(x)=0^2-6(0)+9f(x)=02−6(0)+9
f(x)=9f(x)=9
Substitute x=-1 in above equation
f(x)=(-1)^2-6(-1)+9f(x)=(−1)2−6(−1)+9
f(x)=1+6+9f(x)=1+6+9
f(x)=16f(x)=16
Substitute x=3 in above equation
f(x)=(3)^2-6(3)+9f(x)=(3)2−6(3)+9
f(x)=9-18+9f(x)=9−18+9
f(x)=0f(x)=0
Substitute x=6 in above equation
f(x)=(6)^2-6(6)+9f(x)=(6)2−6(6)+9
f(x)=36-36+9f(x)=36−36+9
f(x)=9f(x)=9
Now draw the graph using the table shown below:
x 0 -1 3 6
f(x) 9 16 0 9
The required graph is shown below
Answer:
hi ma saru
Step-by-step explanation:
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