Draw the graphs of 3x + 2y = 6 and 2x + y = 4. Shade the region bounded by these lines and y-axis. Find the area of shaded region.
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Given : 3x + 2y = 6 and 2x + y = 4.
To Find : area of the region bounded by these lines and y-axis
Solution:
3x + 2y = 6
2x + y = 4
& y axis
Lets find vertex of triangle at y axis x = 0
=> ( 0 , 3) & ( 0 , 4) are vertex of triangle on y axis
x = 2 , y = 0 ( 2, 0) is third Vertex)
Base of triangle = 4 - 3 = 1
Altitude = 2
Area of triangle = (1/2)(1) (2) = 1 sq units
area of shaded region. = 1 sq units
or Area
( 0 , 3) & ( 0 , 4) , ( 2, 0)
Area = (1/2) | 0(4 - 0) + 0(0-3) + 2(3 - 4)| = (1/2) | - 2| = 2/2 = 1
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