Draw the graphs of following pair of equations: 2x + y = 2; 2x + y − 6 = 0. On the same
Answers
Answer:
Thus, we have the following table: x 0 -1 1 y 2 0 4 Now, we plot the points D(0,2), E(-1,0) and F(1,4) on the same graph paper. We join D,E and F and extend it on the both sides to obtain the graph of the equation 2x - y + 2 = 0. It is evident from the graph that the two lines intersect at point F(1,4). The area enclosed by the given lines and x-axis is shown in Fig. above Thus, x = 1, y = 4 is the solution of the given system of equations. Draw FM perpendicular from F on x-axis. Clearly, we have FM = y-coordinate of point F(1,4) = 4 and BE = 4 ∴ ∴ Area of the shaded region = Area of △ △FBE ⇒ ⇒ Area of the shaded region = 1 2 12(Base x Height) = 1 2 12(BE x FM) = ( 1 2 × 4 × 4 ) (12×4×4)sq. units = 8 sq. units.Read more on Sarthaks.com - https://www.sarthaks.com/28097/draw-graph-and-shade-the-region-bounded-these-lines-and-axis-find-the-area-the-shaded-region
Step-by-step explanation:
Step-by-step explanation:
Step-by-step explanation:2x+y-2=0 2x+y-2=0 2x+y-2=0
Step-by-step explanation:2x+y-2=0 2x+y-2=0 2x+y-2=0putting x=0 putting x=1 putting x=2
Step-by-step explanation:2x+y-2=0 2x+y-2=0 2x+y-2=0putting x=0 putting x=1 putting x=20+y-2=0 2+y-2=0 4+y-2=0
Step-by-step explanation:2x+y-2=0 2x+y-2=0 2x+y-2=0putting x=0 putting x=1 putting x=20+y-2=0 2+y-2=0 4+y-2=0y=2 y=0 y=-2
(0,2) (1,0) (2, -2)
second equation:
2x+y-6=0 2x+y-6=0 2x+y-6=0
putting x=0 putting x=1 putting x=2
0+y-6=0 2+y-6=0 4-6+y=0
y=6 y=4 y=2
(0,6) (1,4) ( 2,2)