Question

Draw the graphs of the equations x - 3,x=5 and 2x y 4-0. Also find the area of the quadrilateral formed by the lines and the x-axis.

Answer 1

Given equation of lines x = 3, x = 5 and 2x - y - 4 = 0. Table for line 2x – y – 4 = 0 Plotting the graph, we get, Read more on Sarthaks.com - https://www.sarthaks.com/878888/draw-the-graphs-equations-also-find-the-area-the-quadrilateral-formed-the-lines-and-the-axis

Answer 2

Answer:

answer is: Given equation of lines x = 3, x = 5 and 2x - y - 4 = 0. Table for line 2x – y – 4 = 0 Plotting the graph, we get, From the graph, we get, AB = OB - OA = 5-3 = 2 AD = 2 BC = 6 Thus, quadrilateral ABCD is a trapezium, then, Area of Quadrileral ABCD = ½ × (distance between parallel lines) = ½ × (AB) × (AD + BC) = 8 sq unitsRead more on Sarthaks.com - https://www.sarthaks.com/878888/draw-the-graphs-equations-also-find-the-area-the-quadrilateral-formed-the-lines-and-the-axis?show=878892#a878892

Explanation:

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