Draw the graphs of the equations x - y + 1 = 0) and 3x + 2y - 12 = 0. Determine the
coordinates of the vertices of the triangle formed by these lines and the x-axis, and
shade the triangular region. *also find area of triangle*
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Answer:
Given,
x−y+1=0....(1)
3x+2y−12=0....(2)
put x=0 in (1)
0−y+1=0⇒y=1
(0,1).....(a)
put y=0 in (2)
3x+2(0)−12=0→x=4
(4,0).....(b)
put x=0 in (2)
3(0)+2y−12=0→y=6
(0,6)......(c)
put y=0 in (1)
x−0+1=0⇒x=−1
(−1,0)...(d)
From figure, the vertices of triangle are (−1,0),(2,3),(4,0)
solution
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