Draw the graphs of the following . 2x-y-2=0, 4x+ 3y - 24=0 and y+4=0 obtain the vertices of triangle so formed and its area
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Answer:
It is given
4x+3y=24
We can also write it as
3y=24−4x
y=
3
24−4x
Substituting x=0 in the given equation
y=
3
24−4(0)
So we get
y=
3
24
By division
y=8
Substituting x=3 in the given equation
y=
3
24−4(3)
So we get
y=
3
12
BY division
y=4
x 0 3
y 8 4
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