Question

Draw the graphs of the following . 2x-y-2=0, 4x+ 3y - 24=0 and y+4=0 obtain the vertices of triangle so formed and its area

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Answer 1

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EXPLANATION.

Graph of the equations.

→2x-y-2=0. - (1).

→ 4x + 3y - 24 = 0. ----(2).

→y+4=0.- (3).

As we know that,

From equation (1), we get.

→ 2x -y - 2 = 0.- (1).

Put the values of x = 0 in the equation, we get.

→ 2(0)-y-2=0.

→-y-2=0.

→-y = 2.

⇒ y = -2.

Their Co-ordinates = (0,-2).

Put the value of y = 0 in the equation, we get.

→ 2x - (0) - 2 = 0.

→2x - 2 = 0.

→ 2x = 2.

→ X = 1.

Their Co-ordinates = (1,0).

From equation (2), we get.

4x + 3y - 24 = 0. (2).

Put the values of x = 0 in the equation, we get.

→ 4(0) + 3y - 24 = 0.

→ 3y - 24 = 0.

→ 3y = 24.

⇒ y = 8.

Their Co-ordinates = (0,8).

Put the values of y = 0 in the equation, we get.

→ 4x +3(0) - 24 = 0.

→ 4x-24 = 0.

4x = 24.

→ x = 6.

Their Co-ordinates = (6,0).

From equation (3), we get.

→y + 4 = 0.-- (3).

y = -4.

Their Co-ordinates = (0,-4).

Vertices of triangle formed =(3,4), (0,8), (1,0), (6,0), (0,-2), (-1,-4), (0,-4), (9,-4).

hope it was helpful to you

Answer 2

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Graph of the equations.

→2x-y-2=0. - (1).

→ 4x + 3y - 24 = 0. ----(2).

→y+4=0.- (3).

As we know that,

From equation (1), we get.

→ 2x -y - 2 = 0.- (1).

Put the values of x = 0 in the equation, we get.

→ 2(0)-y-2=0.

→-y-2=0.

→-y = 2.

⇒ y = -2.

Their Co-ordinates = (0,-2).

Put the value of y = 0 in the equation, we get.

→ 2x - (0) - 2 = 0.

→2x - 2 = 0.

→ 2x = 2.

→ X = 1.

Their Co-ordinates = (1,0).

From equation (2), we get.

4x + 3y - 24 = 0. (2).

Put the values of x = 0 in the equation, we get.

→ 4(0) + 3y - 24 = 0.

→ 3y - 24 = 0.

→ 3y = 24.

⇒ y = 8.

Their Co-ordinates = (0,8).

Put the values of y = 0 in the equation, we get.

→ 4x +3(0) - 24 = 0.

→ 4x-24 = 0.

4x = 24.

→ x = 6.

Their Co-ordinates = (6,0).

From equation (3), we get.

→y + 4 = 0.-- (3).

y = -4.

Their Co-ordinates = (0,-4).

Vertices of triangle formed =(3,4), (0,8), (1,0), (6,0), (0,-2), (-1,-4), (0,-4), (9,-4).