Question

draw the graphs of the following equation. 2x-y=1, x+2y =13 find the solution of the equation from the graph and shade the triangular region .... for this i dont need graph plzz wrote the graph points....

Answer 1

Friend the points for the cases are given below:

Case (i)   -     2x - y = 1

(0,-1)  (1,1)  (2,3)
____________________________________________________

Case (ii)   -     x + 2y = 13

(1,6)   (3,5)  (5,4)
____________________________________________________

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Answer 2

Here,
It's given that 2x - y = 1
And x + 2y = 13

So,
In first equation
2x-y =1
2x = 1+y
x = 1+y/2

So 4 values of x and y are
X__0.5____1____2_
Y 0 1 3

Now in 2nd equation
X +2y = 13
Y = 13 - x /2
So,
The 3 value are
(1,6) (3,5) ( 5,4)

So the point to be marked are
(0.5,0) (1,1) (2,3) (1,6) ( 3,5) (5,4)

The triangle is above

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