Question

draw the graphs of the following equations on the same graph sheet x=0 y=0 x+y=4 also find the area enclosed between these lines..please it to urgent I have exam today .

Answer 1

Step-by-step explanation:

i) x = 0 is y -axis ( Red line )

ii ) y = 0 is x-axis .( Blue line )

iii ) x + y = 4( Green line)

If x = 0 then y = 4

If y = 0 then x = 4

plot the points A(4,0) and B(0,4) on a graph ,

we get x-intercept (a) = 4 and y-intercept (b) = 4,

Now,

∆AOB is enclosed by given three lines x = 0 ,y=0 and x+y = 4.

$Area \: of \:\triangle OAB = \frac{1}{2}\times ab$

$= \frac{1}{2}\times 4 \times 4$

$= 2 \times 4 \\=8 \: square \:units$

Therefore.,

$\red { Required \: area \:enclosed \:by \:lines }$

$\green {= 8 \:square \:units }$

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Answer 2

Answer:

Step-by-step explanation:

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