Math, asked by Anonymous, 1 year ago

Draw the graphs of the given polynomial and find the zeroes
(1) ptx) = x^2-x-12 (ii) p(x) = x^2 - 6x + 9
(iii) px) = x^2 - 4x + 5 (iv) plx) = x^2 + 3x-4
(V)(x) = x^2-1​

Answers

Answered by manash99
1

Answer:

v) (x)=x^2-1

Step-by-step explanation:

(1)=1^2-1

=2-1

=1

Answered by Anonymous
8

hey what the hell y r u posting my name in ur questions ....???

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