Question

Draw the graphs of the pair of linear equations 3x+2y=5 and 2x–3y=-1. Determine the coordinates of the vertices of the triangle formed by these linear equations and the X-axis.

Answer 1

Solution:

To draw the line graphically,we have to calculate at least three points/coordinates of each line

1) 3x+2y=5

2y = 5-3x

y = (5-3x)/2 ------- eq1

put x = 1; y =(5-3)/2 =1; (1,1)

put x = -1; y =(5+3)/2 =4; (-1,4)

put x = 3; y =(5-9)/2 =-2; (3, -2)

2) 2x–3y=-1

-3y = -1 -2x

3y = 1+2x

y = (1+2x)/3

put x = 1; y =(1+2)/3 =1; (1,1)

put x =4; y =(1+8)/3 =3; (4,3)

put x =-2; y =(1-4)/3 =-1; ( -2, -1)

Now,we have three coordinates of each line, Draw the lines into graph paper.

The graph is attached.

From graph you can analyse that Triangle form by lines and x -axis

has vertex ( 1,1) ( -0.5, 0) and ( 1.67,0)

Hope it helps you.

Answer 2

Answer:

vertices are A(-3,0),B(-5,0),C(1,0)

solution