Draw the graphs of x – y + 1 = 0 and 3x + 2y - 12 = 0. Determine the
coordinates of the vertices of the triangle formed by these lines and x axis
and shade the triangle.
Answers
EXPLANATION.
Graph of the equation.
⇒ x - y + 1 = 0. - - - - - (1).
⇒ 3x + 2y - 12 = 0. - - - - - (2).
As we know that,
From equation (1), we get.
⇒ x - y + 1 = 0. - - - - - (1).
Put the values of x = 0 in the equation, we get.
⇒ (0) - y + 1 = 0.
⇒ - y + 1 = 0.
⇒ - y = - 1.
⇒ y = 1.
Their Co-ordinates = (0,1).
Put the value of y = 0 in the equation, we get.
⇒ x - (0) + 1 = 0.
⇒ x + 1 = 0.
⇒ x = - 1.
Their Co-ordinates = (-1,0).
From equation (2), we get.
⇒ 3x + 2y - 12 = 0. - - - - - (2).
Put the values of x = 0 in the equation, we get.
⇒ 3(0) + 2y - 12 = 0.
⇒ 2y - 12 = 0.
⇒ 2y = 12.
⇒ y = 6.
Their Co-ordinates = (0,6).
Put the values of y = 0 in the equation, we get.
⇒ 3x + 2(0) - 12 = 0.
⇒ 3x - 12 = 0.
⇒ 3x = 12.
⇒ x = 4.
Their Co-ordinates = (4,0).
Both curves intersects at a point = (2,3).
Given :-
x - y + 1 = 0
3x + 2y - 12 = 0
To Find :-
Determine the coordinates of the vertices of the triangle formed by these lines and x-axis and shade the triangle.
Solution :-
x - y + 1 = 0
x - y = 0 - 1
x - y = -1
Put the value of x as 0
0 - y = -1
-y = -1
y = 1
If x = 0. Then, coordinate = (0,1)
Put the value of y as 0
x - 0 = -1
x = -1
If y = 0. Then, coordinate = (-1,0)
3x + 2y - 12 = 0
3x + 2y = 0 + 12
3x + 2y = 12
Put the value of x as 0
3(0) + 2y = 12
0 + 2y = 12
2y = 12
y = 12/2
y = 6
If x = 0. Then, coordinate = (0,6)
Put the value of y as 0
3x + 2(0) = 12
3x + 0 =12
3x = 12
x = 12/3
x = 4
If y = 0. Then, coordinate = (4,0)