Draw the incirlce of triangle ABC in which AB is a 6cm and
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Ar(triangle) ABC
= 1/2* side* corresponding altitude
= 1/2*BC*AD
= 1/2*5*10………….(1)
Ar(triangle) ABC
= 1/2*AC*BE
= 1/2*6*BE……………(2)
Since (1) = (2)
So, 1/2*5*10 = 1/2*6*BE
=> BE = (5*10) / 6
=> BE = 25/3 = 8.33 cm (approx)
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= 1/2* side* corresponding altitude
= 1/2*BC*AD
= 1/2*5*10………….(1)
Ar(triangle) ABC
= 1/2*AC*BE
= 1/2*6*BE……………(2)
Since (1) = (2)
So, 1/2*5*10 = 1/2*6*BE
=> BE = (5*10) / 6
=> BE = 25/3 = 8.33 cm (approx)
make it brainliest please please
and your question is Incomplete I hope it help you
be brainly
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