Draw the lines y = -2 and y = 6. Find and draw the locus of the point which is equidistant
two given lines
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topic: on application og loci in coordinate geometry
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Answer:
Steps of construction:-
(i) Draw a line segment A of 6m.
(ii) Draw perpendicular bisector LM of AB.LM is the required locus.
(iii) Take any point on LM say O.
(iv) Join OA and OB. Since O lies on the right bisector of the line AB
Therefore, O is equidistant from A and B, i.e.,
OA=OB
Hence perpendicular bisector of AB is the locus of all the points which are equidistant from A and B.
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Step-by-step explanation:
hey dear, there are many solutions............
so, line is parallel or equidistant
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