draw the MO diagram of NO and find out Bond order and stability and also write the electronic configuration .
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Bond order =21[Nb−Na]
Nb= number of bonding electrons
Na= number of anti-bonding electrons
→ Bond order of N2 is 3
→ Bond order of N2− is 2.5
→ Bond order of N2+ is 2.5
Bond order α stability αbondlength1
order of bond length
Ans :- N2+=N2−>N2
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