Question

Draw the molecular orbital diagram of N2 and calculate the bond order
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Answer 1

Answer:

The bond order shows the number of chemical bonds present between a pair of atoms. The Bond Order Formula can be defined as half of the difference between the number of electrons in bonding orbitals and antibonding orbitals.

Bond order formula is given as below

Bondorder=1/2[a–b]

where

a = Number of electrons in bonding molecular orbitals.

b = Number of electrons in antibonding molecular orbitals.

(i) Structure of N2

Electronic configuration of N2 (14 electrons) = (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π)4(2pz)2

a = 10

b= 4

Bond order = 1/2 (10 – 4)

Bond order = 3

Explanation:

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Answer 2

Explanation:

Dual nature of matter implies on matter showing two behaviors:

As a particle

As wave

Matter shows both of these behaviors under certain conditions.  As a particle is generally on Newtonian scale and as aa wave is on quantum scale .

Broglie's principle says that wavelength of a mass is inversely proportional to the momentum of the body. It's given by,

\lambda = \dfrac{h}{mv}λ=mvh

where h=  plank's constant.

Therefore clearly,

\lambdaλ ∝\dfrac{1}{v}v1