Draw the MOT molecular orbital theory of N2+
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Electronic configuration of N-atom(Z=7) is 1 s to the power of 2 space end exponent 2 s squared 2 p subscript x superscript 1 2 p subscript y superscript 1 2 p subscript z superscript 1.
The total number of electrons present in the N2 molecule is 14.
N2+ ion is formed by the loss of one electron from the N2 molecule. This lost electron will be lost from σ(2pz) orbital. Hence, the electronic configuration of N2+ ion will be
N2+ = KK[σ(2s)]2 [σ*(2s)]2 [π(2px)]2 [π(2py)]2 [σ(2pz)]1
Here, Nb =7, Na=2 so that
Bond space order space space equals space space 1 half left square bracket straight N subscript straight b minus straight N subscript straight a right square bracket space space space space space space space
Explanation:
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