Question

Draw the net of a triangular prison whose ends are triangles of dimensions
2 cm * 2 cm x 2 cm (equilateral) and whose length is 5 cm.​

Answer 1

Answer:

Refer to the below image:  

- △DEF =  △BAC        [As they are equilateral]

- Mark the length of each side as given here:

• EF = 2cm
• DE = 2cm
• FD = 2cm
• BA = 2cm
• AC = 2cm
• BC = 2cm

- The length of the prism is 5 as given and so,

• EB = 5cm
• FC = 5cm
• DA = 5cm

- Extras:

• DE = 3cm
• FD = 3cm
• AB = 3cm
• CA = 3cm

_______________________

Hope it helps☺

Answer 2

222222230494o85otbtufbdbshajaqjjqjwje