Math, asked by 9baastha, 29 days ago

Draw the quadrilateral whose vertices are (1,1) (2,4) (8,4) (10,1) find area


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Answered by lamBack
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First draw two perpendicular axis XOX' and YOY', let the vertices of quadrilateral are P(1,1),Q(2,4),R(8,4) and S(10,1)

First draw two perpendicular axis XOX' and YOY', let the vertices of quadrilateral are P(1,1),Q(2,4),R(8,4) and S(10,1)Draw these points of the coordinate axis as shown:

First draw two perpendicular axis XOX' and YOY', let the vertices of quadrilateral are P(1,1),Q(2,4),R(8,4) and S(10,1)Draw these points of the coordinate axis as shown:It is clear from the figure, sides PS and QR are parallel and sides PQ and RS are unequal.

First draw two perpendicular axis XOX' and YOY', let the vertices of quadrilateral are P(1,1),Q(2,4),R(8,4) and S(10,1)Draw these points of the coordinate axis as shown:It is clear from the figure, sides PS and QR are parallel and sides PQ and RS are unequal. Hence given quadrilateral is trapezium.

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