Question

draw the ray diagram when an object is placed at a distance of 40 cm from the optical centre of convex lens of radius of curvature 30cm​

Answer 1

• Explanation:

let 10 cm of question be 1 cm of scale.

then

30 cm(2f) = 3 cm

40 cm = 4 cm

draw the image in convex lens beyond 2f

where f=3/2=1.5cm

object at 4 cm

Answer 2

$i=120\ cm$

the image formed is real inverted and magnified.

Explanation:

Given that:

position of object from the optical center of a convex lens, $o=40\ cm$

radius of curvature of the lens, $r=30\ cm$

Assuming that focal length,  $f=r$

now, using the lens formula:

$\frac{1}{f} =\frac{1}{o} +\frac{1}{i}$

where:

$i=$ position of image

$\frac{1}{30} =\frac{1}{40}+\frac{1}{i}$

$i=120\ cm$

the image formed is real inverted and magnified.

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TOPIC: convex lens

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