Draw the speed time graph of a car from given valuses and calculate
A acceleration of car
B distance travelled between 6th and 10th second
Speed 0. 10. 20. 30. 40. 50. 60.
Time. 0. 2. 4. 6. 8. 10. 12
Please help
rakeshmohata:
value of acceleration*and distance??
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Here the Acceleration A will be 5 m/s²
And the distance travelled between the given time is 200 m
1)
Acceleration is the rate of change in velocity with time..
With incerase in 2 sec of time, velocity increases by 10 from previous one. So..

Here from graph the slope will easily determine the value of acceleration.
_____________________________
2) if the graph is drawn..
Then u will easily get the distance by finding out the area of the enclosed surface u want .
For us we want to find the distance travelled between 6th to 10th second.. So area of graph between 6th to 10 th second will be the answer.
Now watching the graph we can find out the area...
So..

Thus the required distance travelled is 200 m
__________________________
Hope this is ur required answer
Proud to help you
And the distance travelled between the given time is 200 m
1)
Acceleration is the rate of change in velocity with time..
With incerase in 2 sec of time, velocity increases by 10 from previous one. So..
Here from graph the slope will easily determine the value of acceleration.
_____________________________
2) if the graph is drawn..
Then u will easily get the distance by finding out the area of the enclosed surface u want .
For us we want to find the distance travelled between 6th to 10th second.. So area of graph between 6th to 10 th second will be the answer.
Now watching the graph we can find out the area...
So..
Thus the required distance travelled is 200 m
__________________________
Hope this is ur required answer
Proud to help you
Attachments:
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