Physics, asked by srvashwin, 1 year ago

Draw the speed time graph of a car from given valuses and calculate
A acceleration of car
B distance travelled between 6th and 10th second
Speed 0. 10. 20. 30. 40. 50. 60.
Time. 0. 2. 4. 6. 8. 10. 12
Please help


rakeshmohata: value of acceleration*and distance??
srvashwin: yes
srvashwin: distance between 6th and 10th sec
srvashwin: pls do it 9th std way pls sorry to say this

Answers

Answered by rakeshmohata
9
Here the Acceleration A will be 5 m/s²

And the distance travelled between the given time is 200 m

1)

Acceleration is the rate of change in velocity with time..

With incerase in 2 sec of time, velocity increases by 10 from previous one. So..

 =  > a =  \frac{dv}{dt}  =  \frac{10 - 0}{2 - 0}  =  \frac{20 - 10}{4 - 2}  = \blue{ 5m {s}^{ - 1} }
Here from graph the slope will easily determine the value of acceleration.
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2) if the graph is drawn..

Then u will easily get the distance by finding out the area of the enclosed surface u want .

For us we want to find the distance travelled between 6th to 10th second.. So area of graph between 6th to 10 th second will be the answer.

Now watching the graph we can find out the area...

So..

 =  > area \:  \: of \:  \: rectangle + area \:  \: of \:  \: tiangle \\  \\  = \green{ 40 \times 4} +  \green{ \frac{1}{2} \times 4 \times 20 } \\  \\  =  \green{160} +  \green{40} =   \huge{\boxed{ \underline{ \orange{200 \: m}}}}
Thus the required distance travelled is 200 m


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Hope this is ur required answer

Proud to help you

Attachments:

akku1877: Nyc one ../ with Nyc explanation alsi
akku1877: *also
rakeshmohata: thanks alot
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