Chemistry, asked by KHANING, 4 months ago

Draw the structural formula of
an alkane that has
a) six carbons, all secondary
carbons
b) eight carbons and only pri-
mary hydrogens
c) seven carbons with two isopropyl groups
d)six carbons, three primary and three tertiarycarbons

Answers

Answered by patra14825752ote8cm
1

Objectives

After completing this section, you should be able to

recognize and name any alkyl group that can be considered to have been formed by the removal of a terminal hydrogen atom from a straight-chain alkane containing ten or fewer carbon atoms.

explain what is meant by a primary, secondary, tertiary or quaternary carbon atom.

represent the various types of organic compounds using the symbol “R” to represent any alkyl group.

Key Terms

Make certain that you can define, and use in context, the key terms below.

alkyl group

methyl group

isopropyl group

sec-butyl group

isobutyl group

tert-butyl group

primary carbon

secondary carbon

tertiary carbon

quaternary carbon

Study Notes

The differences among primary, secondary, tertiary and quaternary carbon atoms are explained in the following discussion. A convenient way of memorizing this classification scheme is to remember that a primary carbon atom is attached directly to only one other carbon atom, a secondary carbon atom is attached directly to two carbon atoms, and so on.

The IUPAC system requires first that we have names for simple unbranched chains, as noted above, and second that we have names for simple alkyl groups that may be attached to the chains. Examples of some common alkyl groups are given in the following table. Note that the "ane" suffix is replaced by "yl" in naming groups. The symbol R is used to designate a generic (unspecified) alkyl group.

Table 3.4.1 : Alkyl Group names

Group

CH3–

C2H5–

CH3CH2CH2–

(CH3)2CH–

CH3CH2CH2CH2–

(CH3)2CHCH2–

CH3CH2CH(CH3)–

(CH3)3C–

R–

Name

Methyl

Ethyl

Propyl

Isopropyl

Butyl

Isobutyl

sec-Butyl

tert-Butyl

Alkyl

Alkyl Groups

Alkanes can be described by the general formula CnH2n+2. An alkyl group is formed by removing one hydrogen from the alkane chain and is described by the formula CnH2n+1. The removal of this hydrogen results in a stem change from -ane to -yl. Take a look at the following examples.

NamingAlkanes-Alkyl.gif

The same concept can be applied to any of the straight chain alkane names provided in Table 3.4.2 .

Table 3.4.2 : straight chain alkane

Methane

CH4

CH4

Ethane

C2H6

CH3CH3

Propane

C3H8

CH3CH2CH3

Butane

C4H10

CH3(CH2)2CH3

Pentane

C5H12

CH3(CH2)3CH3

Hexane

C6H14

CH3(CH2)4CH3

Heptane

C7H16

CH3(CH2)5CH3

Octane

C8H18

CH3(CH2)6CH3

Nonane

C9H20

CH3(CH2)7CH3

Decane

C10H22

CH3(CH2)8CH3

Undecane

C11H24

CH3(CH2)9CH3

Dodecane

C12H26

CH3(CH2)10CH3

Tridecane

C13H28

CH3(CH2)11CH3

Tetradecane

C14H30

CH3(CH2)12CH3

Pentadecane

C15H32

CH3(CH2)13CH3

Hexadecane

C16H34

CH3(CH2)14CH3

Heptadecane

C17H36

CH3(CH2)15CH3

Octadecane

C18H38

CH3(CH2)16CH3

Nonadecane

C19H40

CH3(CH2)17CH3

Eicosane

C20H42

CH3(CH2)18CH3

Answered by MagicalBeast
2

Answer:

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