Draw the structure of BrF4 − .
Answers
Answer:
Its structure will be like that
The Lewis structure of the tetrafluoroborate ion, BrF4.
The molecule will have a total of 36 valence electrons - 7 from bromine, 7 from each of the four fluorine atoms, and one extra electron to give the ion the -1 charge.
The bromine atom will be bonded to each of the four fluorine atoms via single bonds for a total of 8 of the 36 valence electrons. The fluorine atoms will each have 3 lone pairs attached, bringing the number of used valence electrons to 32.
The remaining 4 valence electrons will be placed on bromine as lone pairs.
The bromine atom is surrounded by 6 regions of electron density - four single bonds and 2 lone pairs, which means that its steric number will be equal to 6.
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