Question

draw the structure of: (i) 5-Amino-4-bromo-3-chloro-2-formyl-cyclopent-3-ene-1-carboxylic acid​

Answer 1

Answer:

Answer in photo:

Explanation:

5-NH-4-Br-3-Cl-2-

Answer 2

Answer:

bruh your naming is wrong correct naming will be 2 amino 3 bromo 4 chloro 5 formylcyclopent 3 enecarboxylic acid

Explanation:

because when you have taken carboxylic acid as the main functional group all other functional group become substituent group and will be considered as prefix 2 so if you thought that CHO should more priority then forget it priority will be given according to alphabetical order and about the structure others have already posted it