Question

Draw the structure of the following molecule and mention molecule and mention its shape.

XeF4​

Answer 1

ANSWER ☺️

Structure of XeF4

⏺️Square planar

HOPE it helps ✔️❣️

Answer 2

Lewis structure of XeF4

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Step method to draw lewis structure of Xenon tetrafluoride

Step method to draw lewis structure for XeF4( This molecules is an example of expanded octet)

Step 1: Find valence e- for all atoms. Add them together.

Xe:8

F:7x4=28

Total=36

Step2: Find octet e- for each atom and add them together.

Xe=12

F:8x4=32

Total=44

Bromine gets 12 electrons in order to make 5 bonds with surrounding atoms.

Step3: Gives you bonding e-. Subtract step 1 total from step 2

44-36=8e-

Step 4: Find number of bonds by diving the number in step 3 by 2(because each bond is made of 2 e-)

8e-/2= 4 bond pairs

Step 5: Find the number of nonbonding (lone pairs) e-. Subtract step 3 number from step 1.

36-8= 28e-=14 lone pairs

Use information from step 4 and 5 to draw the lewis structure.

Shape of XeF4:

XeF4 has a square planar shape with dsp2 hybridisation.