Question

Draw the structure of XeF2 ,XeF4 and XeF6​

Answer 1

Answer:

Xenon Difluoride is a chemical compound with the formula XeF2. It was discovered in the year 1962. It is a powerful fluoridating agent. XeF2 was considered to be a possible convenient replacement for elemental fluorine especially in addition reactions to a double bond. The oxidation state of xenon in Xenon Difluoride is +2. Xenon tetrafluoride has a negligible vapour pressure at -78° and about 3 mm-Hg at room temperature. Xenon difluoride is a hazardous chemical, reacting with water moisture to form hydrofluoric acid.

Other names – Difluoroxenon, Xenon fluoride

XeF2 Xenon Difluoride

Density 4.32 g/cm³

Molecular Weight/ Molar Mass 169.29 g/mol

Boiling Point 155 °C

Melting Point 128.6 °C

Chemical Formula XeF2

Xenon Difluoride Synthesis – XeF2

When a mixture of xenon and fluorine in the ratio of 2:1 is heated at 400oC in a sealed nickel vessel, XeF2 is formed.

Xe + F2 → XeF2

Answer 2

Question:

Stuructures of  XeF2,XeF4 and XeF6.

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Xe has total of 8 valence electrons.

In XeF2,  2 electrons are shared thereby leaving three lone pair of electrons.

In XeF4,  4 electrons are shared thereby leaving two lone pair of electrons.

In XeF6,  6 electrons are shared thereby leaving one lone pair of electrons.

Hence, No of lone pair of electrons in XeF2, XeF4, XeF6 are 3,2,1 respectively.

Note: Figures showing lone pairs are attached to get a better idea.