Draw the structures of the following compound: 3-Bromo-4-phenylpentanoic acid
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The 3-Bromo-4-phenylpentanoic acid structure can be formed by the H3C then CH which will be connected to the ring of the 6-carbon atom (C6H5).
This will be connected with CHBr – CH2 – C=O - OH.
You can try to form a structure with these guidelines. Just make sure to place them correctly.
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