Question

Draw the
the graph for
the equation x-y+ 1 = 0
When x=0,1,2,3,4,5​

Answer 1

Answer:For equation x–y+1=0 or x=y−1, we have following points which lie on the linePlug y=0,1 we getx=0−1=−1x=1−1=0Therefore, the required points are (−1,0),(0,1). For equation 3x+2y–12=0 or y=212−3x, we have following points which lie on the linePlug x=0,4 we gety=212−0=6y=212−12=0Therefore, the required points are (0,6),(4,0).We can see from the graphs that points of intersection of the lines with the x–axis are (–1,0),(2,3) and (4,0).

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Answer 2

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